# Line slope calculator 5x+6y=58

**Straight line given by points A[2; 8] and B[8; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.8333x+9.6667

**Canonical form of the line equation:**5x+6y-58 = 0

**Parametric form of the line equation:**

x = 6t+2

y = -5t+8 ; t ∈ R

**Slope:**m = -0.8333

**Slope angle of line: φ =**-39°48'20″ = -0.6947 rad

**X intercept:**x

_{0}= 11.6

**Y intercept:**y

_{0}= q = 9.6667

**Distance line from the origin:**d

_{0}= 7.4261

**The length of the segment AB: |AB| =**7.8102

**Vector: AB =**(6; -5)

**Normal vector: n =**(5; 6)

**Midpoint of the segment AB: M =**[5; 5.5]

**Perpendicular Bisector equation:**6x-5y-2.5 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (8; 3) ; |OB| = 8.544**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 55°24'28″ = 0.967 rad**